This time i choose an array question. quite an easy one.

Return true if the group of N numbers at the start and end of the array are the same. For example, with {5, 6, 45, 99, 13, 5, 6}, the ends are the same for n=0 and n=2, and false for n=1 and n=3. You may assume that n is in the range 0..nums.length inclusive.

sameEnds({5, 6, 45, 99, 13, 5, 6}, 1) → false

sameEnds({5, 6, 45, 99, 13, 5, 6}, 2) → true

sameEnds({5, 6, 45, 99, 13, 5, 6}, 3) → false

A loop should be used , in each pass we must compare two elements of the array which must be equal , Trick is to figure out the relation between the indices of two elements.

1: public boolean sameEnds(int[] nums, int n) {2:3: boolean b=true;4: if(n==0) return b;5: if(n>nums.length) return false;6:7: for(int i=0 ; i<n ; i++){8: if( nums[i] != nums[nums.length-n+i] )9: b=false;10: }11:12: return b;13: }

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